- Calculate Size of Pump having following Details
- Static Suction Head(h2)=0 Meter
- Static Discharge Head (h1)=50 Meter.
- Required Amount of Water (Q1)=300 Liter/Min.
- Density of Liquid (D) =1000 Kg/M3
- Pump Efficiency (pe)=80%
- Motor Efficiency(me)= 90%
- Friction Losses in Pipes (f)=30%
Calculations:
- Flow Rate (Q) =Q1x1.66/100000 =300×1.66/100000= 0.005 M3/Sec
- Actual Total Head (After Friction Losses) (H) = (h1+h2)+((h1+h2)xf)
- Actual Total Head (After Friction Losses) (H)=50+(50×30%)= 65 Meter.
- Pump Hydraulic Power (ph) = (D x Q x H x9.87)/1000
- Pump Hydraulic Power (ph) = (1000 x 0.005 x 65 x9.87)/1000 =3KW
- Motor/ Pump Shaft Power (ps)= ph / pe = 3 / 80% = 4KW
- Required Motor Size: ps / me =4 / 90% = 4.5 KW
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Required Size of Motor Pump = 4.5 HP or 6 HP
View more at https://electricalnotes.wordpress.com/2019/08/15/calculate-motor-pump-size/.
Published by Department of EEE, ADBU: tinyurl.com/eee-adbu
